Quote Originally Posted by Naya Din View Post
Dear Captain Tony,

Thank you for your reply. I have a problem to calculate equivalent length of the shell.

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Basically, the equivalent length of the shell = (The length from T to T) + 1/3*(2*the depth of the head)

Example: A Horizontal Pressure Vessel, T to T = 3000 mm, ID = 1500 mm, 2:1 Elliptical Head

So that, the depth of the 2:1 elliptical head = 1/4 ID = 1500/4 =375 mm
The equivalent length of the shell shall be = 3000 + 1/3(2*375) = 3250 mm

Hope this help.