Max. External Pressure of Pressure Vessel's Shell/Head

[Naya Din]

Dear all members,

Please help me, how to calculate the max. external pressure of shell and head in pressure vessel?
where
internal design pressure: 45psi
Design temperature: 265 deg. F
inside diameter: 60 in
corrosion allowance: 0 in
shell length: 81 in
design external pressure: 4.57psi
nominal shell thickness: 0.135 in

Thanks

[CaptainTony]

Dear Naya Din,
To calculate MAEP for shell, you can use UG-28 ASME Section VIII-Div. 1.

To calculate MAEP for head, you can use UG-33 ASME Section VIII-Div. 1.

Hope this help.

[CaptainTony]

Dear Naya Din,
To calculate MAEP for shell, you can use UG-28 ASME Section VIII-Div. 1.

To calculate MAEP for head, you can use UG-33 ASME Section VIII-Div. 1.

Hope this help.

[Naya Din]

Dear Captain Tony,

Thank you for your reply. I have a problem to calculate equivalent length of the shell.

[Naya Din]

....

[CaptainTony]

Dear Captain Tony,

Thank you for your reply. I have a problem to calculate equivalent length of the shell.

[link Point to another website Only the registered members can access]
Basically, the equivalent length of the shell = (The length from T to T) + 1/3*(2*the depth of the head)

Example: A Horizontal Pressure Vessel, T to T = 3000 mm, ID = 1500 mm, 2:1 Elliptical Head

So that, the depth of the 2:1 elliptical head = 1/4 ID = 1500/4 =375 mm
The equivalent length of the shell shall be = 3000 + 1/3(2*375) = 3250 mm

Hope this help.

[CaptainTony]

Dear Captain Tony,

Thank you for your reply. I have a problem to calculate equivalent length of the shell.

[link Point to another website Only the registered members can access]
Basically, the equivalent length of the shell = (The length from T to T) + 1/3*(2*the depth of the head)

Example: A Horizontal Pressure Vessel, T to T = 3000 mm, ID = 1500 mm, 2:1 Elliptical Head

So that, the depth of the 2:1 elliptical head = 1/4 ID = 1500/4 =375 mm
The equivalent length of the shell shall be = 3000 + 1/3(2*375) = 3250 mm

Hope this help.