scf/bbl to mol/mol

[intel2]

Hello,

can someone help me convert scf/bbl to mol/mol ( its the loading of H2S in DEA)


Thank you

[walead]

It is easiest if you split the problem into two halves - first work out how many mols of H2S you have, and then how many mols of DEA.At standard temperature and pressure you can assume your gas is ideal and use the ideal gas law, i.e. PV=nRT. Taking standard conditions as 60F (519.67 Rankine) and 14.7 psia and R=10.7316 you will see that the volume of one lb mol of gas at STP is 379.4 ft3/lb mol. So if you divide your scf of H2S by 379.4 you have the number of lb mols of H2S.Now, looking at the DEA (assuming you mean diethanolomine) with a molecular weight of 105.14 and a density of 67.4 lb/ft3. A barrel is 5.615 ft3. This makes 1 bbl of DEA 1 x 5.615 x 67.4 /105.14 = 3.60 lb molFrom the first step you have the number of mols per bbl, so divide that answer by 3.6 and you have your answer in mol/mol. Or you could combine the two factors and just divide the value in scf/bbl by 1366 (=379.4 x 3.60) to get the answer directly. Answer on the Net