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Thread: Calculate pressure drop in steam distribution pipe lines

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    Calculate pressure drop in steam distribution pipe lines

    The pressure drop in saturated steam distribution pipes can be calculated in metric units as
    dp = 0.6753 106 q2 l (1 + 91.4/d) / ρ d5 (1)
    where
    dp = pressure drop (Pa)
    q = steam flow rate (kg/h)
    l = length of pipe (m)
    d = pipe inside diameter (mm)

    ρ = steam density (kg/m3)
    Note that the pressure drop calculated might be higher than the actual values at higher velocities.
    The Unwin formula can also be expressed in imperial units as
    dp = 0.0001306 q2 l (1 + 3.6/d) / (3600 ρ d5)(2)
    where
    dp = pressure drop (psi)
    q = steam flow rate (lb/hr)
    l = length of pipe (ft)
    d = pipe inside diameter (inches)

    ρ = steam density (lb/ft3)
    [h=Example - Pressure Drop in Steam Pipe]3[/h] Steam, 4000 kg/h at 10 bar (1000 kPa) pressure with density 5.15 kg/m3 flows through a schedule 40, ND 100 steel pipe, inside diameter 102 mm and length 100 m. The pressure drop can be calculated as
    dp = 0.6753 106 (4000 kg/h)2 (100 m) (1 + 91.4/(102 mm)) / ((5.15 kg/m3) (102 mm)5 )
    = 36030 Pa
    = 36 kPa
    Last edited by Esam; 07-26-2011 at 04:42 PM.

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