Hydrocarbon Losses Quantification (Low Pressure Storage)

[Abel Yasells]

Hi,

Any ideas / calculation methodology to estimate hydrocarbon losses out large diameter liquid storage tanks? I need to quantify any dampening to vapor generation considering factors such as insulation.

Thanks a lot.

[irma reyes martinez]

Th3 equation i liked is w=370×(deltaP ×density ×d^5)^0.5
W=flow in lb÷h
DeltaP=friction loss in lb÷in^2(psi) per 100 ft
Density
D=inside diameter of pipe in inches
This is a form of Fanning or Darcy formula with friction factor=0.0055
This friction factor corresponds to approximately the following
Commercial steel pipes
No. Reynolds=10^5
Williams and Hazen C factor=110
For other friction factors multiply the right sid3 for
(0.0055÷friction factor)^0.5
The friction factor can b3 approximaTed by
Laminar flow f=16÷Re
Commercial pipes f=0.054÷Re^0.2
Smooth tubes f=0.046÷Re^.2
Extremely rough pipes f=0.013
Where Re is the well known. In this case
Friction factor=hl÷(4×(L÷D)×(u^2÷(2g)))
hl÷friction head in feet
L length in Feet
D diameter in feet

[irma reyes martinez]

Be careful wh3n applying the friction factor. Sometim3s it is d3finid aa
f=hl÷((L÷D)(u^2÷(2×g))
For compressible fluids fo3 non critical flow deltap less to 10% P1
P1= upstream pressure, psia
If deltaP major to 10% P1
DeltaP=P1-P2=2×P1÷(P1+P2)×(0.323×(fL÷d+ln(P1÷P2)÷24× S1×U1^2)
Assusme isothermal flow of ideal gas
S1 especific gravity
d pipe diameter
f friction factor
L length of pipe
DeltaP=Pressure dropt 7n psi
M m8lecular wt.
P1,P2=Upstream and downstream pressure in psi ABS
S1 relative to water = 0.00150