In my opinion your problem may be solved as following:
Given some value of P => calculation Z => calculation P' from (P/Z)know=> Abs(P-P') and do the calculation again until Abs(P-P')<e(definition).
In my opinion your problem may be solved as following:
Given some value of P => calculation Z => calculation P' from (P/Z)know=> Abs(P-P') and do the calculation again until Abs(P-P')<e(definition).
Bookmarks