Recent Blogs Posts

1. Api 602

by , 02-18-2020 at 02:44 PM
Anybody can share API 602 latest available?
2. E3D VIDEO & PDF TUTORIAL

by , 01-04-2020 at 07:30 PM (piping software installation.)
3. How to install Vortex Breaker

by , 10-26-2018 at 08:59 PM
[B]Hi friends
Outlet line from a vessel is horizontal for considering a vortex breaker what we must do?
if vortex breaker install vertically is it work?
or it should be install horizontally parallel to liquid surface.
thanks
[/B]
4. Cost Estimation for Oil & Gas Facilities

by , 05-27-2018 at 11:21 PM
Dear Friends and Colleagues,

I need some database through which I can estimate costs of Oil & Gas Processing facilities like de-hydration plants, Dew Pointing Plants, Inlet Separators, Amine Units, Storage, Gas Compression, Gas metering etc. etc. Cost accuracy is no too much refined, only required for conceptual phase economics.

Comments and suggestions would be appreciated.
5. Handbook pressure vessel by Uegene F. Megyesy 14th edition

by , 02-26-2018 at 01:50 AM
Hi everyone

can someone share handbook of megyesy 14th edition, i just have 12th edition. so i need the latest book.
many thankful if someone can share it
6. Request for PQR WPS & WQR for ASME and EN ISO

by , 09-20-2017 at 08:27 PM
Originally Posted by CANDICEDALAIS
Hi guys* can someone please upload a library of PQR WPS and Welders qualifications for ASME and EN ISO
for half inch; 2 inch ; and 6 inch carbon Steel and stainless steel pipe. As well as a few plates that are carbon Steel and stainless steel. Pdf. Would be great.
7. EN13480-3 Tee Branch Reinforcement Pad Calculation

by , 05-31-2017 at 01:03 PM
Hello*

I am doing the branch tee reinforcement pad requirement calculation according to EN 13480-3 section 8.4.3. I have some queries as below.

(1) In Equation 8.4.3-4 ( lpl <= ls). I have calculated the effective reinforcement of shell pipe (ls) value according to equation 8.4.1-2 which is coming around 190 mm. So According to the equation I can use the reinforcement pad width less than ls means less than 190 mm. If I follow the above equation * it will never satisfy the final equation 8.4.3-6. it seems this equation is not correct.
If code restrict the reinforcement pad width how we can satisfy the final equation without increasing the pad width where reinforcement pad width is also limited to eas according to equation 8.4.3-5. Refer attached code page attachment (EN13480-3-Page-82.pdf). Please suggest.

(2) EN13480-3 equation 8.4.3-5 condition eapl<=eas shall be satisfy.
I am using the reinforcement pad thickness same as shell thickness* means pad will be cut from shell pipe during fabrication.

I am using the nominal pad thickness same as shell thickness 16 mm with assuming same corrosion allowances. Refer below calculation.
My nominal shell thickness en=16 mm. c0=3.4* c1=0.3 mm.so eas=16-3.4-0.3= 12.3 mm.
Plate thickness used enpl=16mm. c0=3.4* c1=0.3 mm. so eapl=12.3 mm.

Is my calculation & understanding is correct.

As in brief above code restrict the reinforcement pad thickness as well as width to compensate the cutting area for branch.

8. EN13480-3 Tee Branch Reinforcement Pad Calculation

by , 05-31-2017 at 01:02 PM
Hello*

I am doing the branch tee reinforcement pad requirement calculation according to EN 13480-3 section 8.4.3. I have some queries as below.

(1) In Equation 8.4.3-4 ( lpl <= ls). I have calculated the effective reinforcement of shell pipe (ls) value according to equation 8.4.1-2 which is coming around 190 mm. So According to the equation I can use the reinforcement pad width less than ls means less than 190 mm. If I follow the above equation * it will never satisfy the final equation 8.4.3-6. it seems this equation is not correct.
If code restrict the reinforcement pad width how we can satisfy the final equation without increasing the pad width where reinforcement pad width is also limited to eas according to equation 8.4.3-5. Refer attached code page attachment (EN13480-3-Page-82.pdf). Please suggest.

(2) EN13480-3 equation 8.4.3-5 condition eapl<=eas shall be satisfy.
I am using the reinforcement pad thickness same as shell thickness* means pad will be cut from shell pipe during fabrication.

I am using the nominal pad thickness same as shell thickness 16 mm with assuming same corrosion allowances. Refer below calculation.
My nominal shell thickness en=16 mm. c0=3.4* c1=0.3 mm.so eas=16-3.4-0.3= 12.3 mm.
Plate thickness used enpl=16mm. c0=3.4* c1=0.3 mm. so eapl=12.3 mm.

Is my calculation & understanding is correct.

As in brief above code restrict the reinforcement pad thickness as well as width to compensate the cutting area for branch.

Attached Files
9. Valuable training material for petroleum cmmunity

by , 03-06-2017 at 07:41 PM
Dears*

I have 15 days access for

petroskillseuniversity.activelearner.com/

Here very valuable training material is available.